g est la fonction x⇒x(4x-1) Calculer : a) g(2)    b) g(0)    c) g(-3)    d) g(1/2) Merci d'avance !!!

g(2) = 2(4x2-1) = 14

g(0) = 0(4x0-1) = 0

g(-3) = -3(4x(-3) - 1) = 39

g(1/2) = (1/2)(4x(1/2) - 1) =1/2

Bonsoir,

[tex]g(x)=x(4x-1)\\\\\\a)\ g(2)=2(4\times2-1)\\g(2)=2(8-1)\\g(2)=2\times 7\\\boxed{g(2)=14}\\\\b)\ g(0)=0(4\times0-1)\\g(0)=0\times(0-1)\\\boxed{g(0)=0}[/tex]

[tex]c)\ g(-3)=-3(4\times(-3)-1)\\g(-3)=-3(-12-1)\\g(-3)=-3\times (-13)\\\boxed{g(-3)=39}\\\\d)\ g(\dfrac{1}{2})=\dfrac{1}{2}(4\times\dfrac{1}{2}-1)\\\\g(\dfrac{1}{2})=\dfrac{1}{2}(2-1)\\\\g(\dfrac{1}{2})=\dfrac{1}{2}\times 1\\\\\boxed{g(\dfrac{1}{2})=\dfrac{1}{2}}[/tex]