Mathématiques

Question

inventer trois equations du premier degre a une inconnue qui admettent 2 pour solution

2 Réponse

  • 4x - 4 = 2x
    4x - 2x = 4
    2x = 4
    x = 4/2
    x = 2

    3x - 1 = 2x + 1
    3x - 2x = 1 + 1
    x = 2

    - x + 6 = 8 - 2x
    - x + 2x = 8 - 6
    x = 2
  • - x + 14 = - 2x + 16
    - x + 2x = 16 - 14
    x = 2

    12x + 6 = 10x + 10
    12x - 10x = 10 - 6
    2x = 4
    x = 2

    20 + 3x = 2x + 22
    3x - 2x = 22 - 20
    x = 2

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