Mathématiques

Question

(2t−4)au carré+u(3v−4t)
merci d'avance

1 Réponse

  • (2t-4) au carré = (2t-4) (2t-4)
    Soit 2t*2t +2t*-4+-4*2t+-4*-4
    = 4t^2 -8t -8t +16
    = 4t^2 -16t+16

    u(3v-4t) = u*3v + u*-4t
    = 3uv -4ut

    (2t-4) au carré + u(3v-4t)
    = 4t^2 -16t+16 + 3uv -4ut

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