Mathématiques

Question

Calculer en respectant les priorités.
A=4 (x -5 )=
B=3 (2 x + 6)=
C=5(x-2)=
D= 8(4+2y)=
E= 7 (x +8)=
F=7 (a -4)=
G= 8 (x + 3)=
H= 6(y-3)=
I=(5-x) × 9=
J= (a+4)×7=
K= 9 (3x +5)=
L= 7 (2 - 6 y )=
M = ( 2x + 3 ) ×8=
N = 15 (a - 2 b ) =

2 Réponse

  • Calculer en respectant les priorités. 
    A=4 (x -5 )= 4x-4*5= 4x-20
    B=3 (2 x + 6)= 3*2x+3*6 = 6x+18
    C=5(x-2)= 5x-5*2 = 5x-10
    D= 8(4+2y)= 8*4+8*2y = 32+16y
    E= 7 (x +8)= 7x+7*8 = 7x+56
    F=7 (a -4)= 7a-7*4 = 7a-28
    G= 8 (x + 3)= 8x+8*3 = 8x+24
    H= 6(y-3)= 6y-6*3 = 6y-18
    I=(5-x) × 9= 5*9-9x = 45-9x
    J= (a+4)×7= 7a+4*7 = 7a+28
    K= 9 (3x +5)= 9*3x+9*5 = 27x+45
    L= 7 (2 - 6 y )= 7*2-7*6y = 14-42y
    M = ( 2x + 3 ) ×8= 2*8x+3*8 =16x+24
    N = 15 (a - 2 b ) =15a-15*2b =15a-30b
  • A= 4(x-5)
    = 4x -20

    B= 3(2x +6)
    = 6x +18

    C= 5(x-2)
    = 5x -10

    D= 8(4+2y)
    32 +16y

    E= 7(x+8)
    = 7x +56

    F= 7(a-4)
    = 7a -28

    G= 8(x+3)
    = 8x +24

    H= 6(y-3)
    = 6y -18

    I= (5-x) *9
    = 45 -9x

    J= (a+4)*7
    = 7a +28

    K= 9(3x+5)
    = 27x +45

    L= 7(2-6y)
    = 14 -42y

    M= (2x+3)*8
    = 16x +24

    N= 15(a-2b)
    = 15a -30b





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