Mathématiques

Question

bonjour
merci d'avance,
H=3-2/3
/
4/3*7


J=2/3/5/6-2/5


K= -3/4+1/2
/
2/5-5/2

1 Réponse

  • Bonjour

    H=(3-2/3)  : (4/3*7 )

    H = [(3 x 3) / (1 x 3) - 2/3] : 28/3

    H = (9/3 - 2/3) : 28/3

    H = 7/3 : 28/3

    H = 7/3 x 3/28

    H = 21/84

    H = (21 x 1) / (21 x 4)

    H = 1/4

    J=2/3/5/6-2/5

    J = 2/3 x 6/5 - 2/5

    J = 12/15 - (2 x 3) / (5 x 3)

    J = 12/15 - 6/15

    J = 6/15

    J = (3 x 2) / (3 x 5)

    J = 2/5

    K= (-3/4+1/2 ) : (2/5-5/2)

    K = [- 3/4 + (1 x 2) / (2 x 2)] : [(2 x 2) / (5 x 2) - (5 x 5) / (2 x 5)]

    K = (- 3/4 + 2/4) : (4/10 - 25/10)

    K = - 1/4 : (- 21/10)

    K = - 1/4 x (- 10/21)

    K = 10/84

    K = (2 x 5) / (2 x 42)

    K = 5/42.

Autres questions